{"common":{"save":0,"post_id":"5811","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8538","post_id":"5811","mon_id":"1158532","chapter_id":"1158660","question":"<p>Vi\u1ebft \u0111a th\u1ee9c bi\u1ec3u di\u1ec5n ph\u1ea7n di\u1ec7n tích S màu xanh phía trong khung trang \u1edf hình d\u01b0\u1edbi<\/p><p><span class=\"svgedit\"><svg height=\"170\" width=\"260\"> <g><title><\/title><rect fill=\"#fff\" height=\"172\" id=\"canvas_background\" width=\"262\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" id=\"canvasGrid\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" id=\"svg_2\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g><title><\/title><g id=\"svg_18\"> <g id=\"svg_19\"> <rect fill=\"#fff\" height=\"99\" id=\"svg_1\" stroke=\"#000\" stroke-width=\"1.5\" width=\"178\" x=\"25\" y=\"22.25\"><\/rect> <path d=\"m25.6,50.71713l51.84183,-28.70338l73.31634,0l51.84183,28.70338l0,40.59322l-51.84183,28.70338l-73.31634,0l-51.84183,-28.70338l0,-40.59322z\" fill=\"#aaffd4\" id=\"svg_3\" stroke=\"#000\" stroke-width=\"1.5\"><\/path> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"24\" id=\"svg_5\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"104\" xml:space=\"preserve\" y=\"80.25\">S<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_6\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"45\" xml:space=\"preserve\" y=\"15.25\">2x<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_7\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"176\" xml:space=\"preserve\" y=\"13.25\">2x<\/text> <text 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stroke-width=\"0\" text-anchor=\"start\" x=\"245\" xml:space=\"preserve\" y=\"78.25\">6<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_17\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"112\" xml:space=\"preserve\" y=\"167.25\">8<\/text> <\/g> <\/g> <\/g> <\/svg><\/span><\/p>","options":["<strong>A.<\/strong> S = 48 - 4x²","<strong>B. <\/strong>S = 4x²","<strong>C.<\/strong> S = 48 - 8x²","<strong>D.<\/strong> S = 8x²"],"correct":"1","level":"3","hint":"<p>Tính di\u1ec7n tích c\u1ee7a hình ch\u1eef nh\u1eadt bên ngoài, tính di\u1ec7n tích c\u1ee7a các hình tam giác nh\u1ecf màu tr\u1eafng. S b\u1eb1ng di\u1ec7n tích hình ch\u1eef nh\u1eadt tr\u1eeb di\u1ec7n tích c\u1ee7a các tam giác nh\u1ecf.<\/p>","answer":"<p>Di\u1ec7n tích c\u1ee7a hình ch\u1eef nh\u1eadt bên ngoài là<\/p><p>6 . 8 = 48<\/p><p>Vì các tam giác nh\u1ecf màu tr\u1eafng là các tam giác vuông có hai c\u1ea1nh góc vuông l\u1ea7n l\u01b0\u1ee3t là x và 2x nên di\u1ec7n tích c\u1ee7a m\u1ed9t tam giác nh\u1ecf màu tr\u1eafng là <\/p><p><span class=\"math-tex\">$\\dfrac{1}{2}$<\/span> . x . 2x = x²<\/p><p>Vì b\u1ed1n tam giác nh\u1ecf b\u1eb1ng nhau nên t\u1ed5ng di\u1ec7n tích các tam giác là <\/p><p>4 . x² = 4x² <\/p><p>Di\u1ec7n tích S màu xanh là<\/p><p>S = 48 - 4x²<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>A.<\/strong> S = 48 - 4x²<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-01 09:20:59","option_type":"txt","len":2},{"id":"8552","post_id":"5811","mon_id":"1158532","chapter_id":"1158660","question":"<p>Tìm \u0111a th\u1ee9c P bi\u1ebft M + P = N và <\/p><p>M = <span class=\"math-tex\">$x^3 - 5x^2 + x + 2$<\/span> ; N = <span class=\"math-tex\">$5x^3 - x^2 + 8x - 3$<\/span><\/p>","options":["<strong>A.<\/strong> P = <span class=\"math-tex\">$4x^3+4x^2+7x-5$<\/span>","<strong>B.<\/strong> P = <span class=\"math-tex\">$6x^3-6x^2+9x-1$<\/span>","<strong>C. <\/strong>P = <span class=\"math-tex\">$-4x^3-4x^2-7x+5$<\/span>","<strong>D. <\/strong>P = <span class=\"math-tex\">$-6x^3+6x^2-9x+1$<\/span>"],"correct":"1","level":"3","hint":"<p>M + P = N ⇒ P = N - M<\/p>","answer":"<p>M + P = N ⇒ P = N - M<\/p><p>Do \u0111ó P = (<span class=\"math-tex\">$5x^3 - x^2 + 8x - 3$<\/span>) – (<span class=\"math-tex\">$x^3 - 5x^2 + x + 2$<\/span>)<\/p><p> = <span class=\"math-tex\">$5x^3 - x^2 + 8x - 3 - x^3 + 5x^2 - x - 2$<\/span><\/p><p> = <span class=\"math-tex\">$5x^3 - x^3 - x^2 + 5x^2 + 8x - x - 3 - 2$<\/span><\/p><p> = <span class=\"math-tex\">$4x^3 + 4x^2 + 7x - 5$<\/span><\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>A.<\/strong> P = <span class=\"math-tex\">$4x^3+4x^2+7x-5$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-01 10:12:23","option_type":"math","len":0},{"id":"8554","post_id":"5811","mon_id":"1158532","chapter_id":"1158660","question":"<p>Bi\u1ebft M + P = N và M = <span class=\"math-tex\">$x^3 - 5x^2 + x + 2$<\/span> ; N = <span class=\"math-tex\">$5x^3 - x^2 + 8x - 3$<\/span> .<\/p><p>H\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c P là<\/p>","options":["4","5","0","3"],"correct":"1","level":"3","hint":"<p>M + P = N ⇒ P = N - M<\/p>","answer":"<p>Ta có M + P = N <\/p><p>Do \u0111ó P = N – M<\/p><p> = (<span class=\"math-tex\">$5x^3 - x^2 + 8x - 3$<\/span>) – (<span class=\"math-tex\">$x^3 - 5x^2 + x + 2$<\/span>)<\/p><p> = <span class=\"math-tex\">$5x^3 - x^2 + 8x - 3 - x^3 + 5x^2 - x - 2$<\/span><\/p><p> = <span class=\"math-tex\">$5x^3 - x^3 - x^2 + 5x^2 + 8x - x - 3 - 2$<\/span><\/p><p> = <span class=\"math-tex\">$4x^3 + 4x^2 + 7x - 5$<\/span><\/p><p>V\u1eady h\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a P là 4<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong> 4<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-01 10:15:26","option_type":"number","len":0}]}