Bài tập cơ bản bài Tiên đề Ơ-clit về đường thẳng song song

Home Lớp 7 Toán lớp 7 - Sách cũ Tiên đề Ơ-clit về đường thẳng song song

{"segment":[{"time":24,"part":[{"time":3,"title":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","title_trans":"Cho c\u00e1c g\u00f3c $\\widehat{xOy} $ v\u00e0 $ \\widehat{mIn}$ l\u00e0 hai g\u00f3c c\u00f3 c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng song song c\u00f9ng nh\u1ecdn. C\u00f3 Ox \/\/ Im, Oy \/\/ In. <br\/> H\u00e3y s\u1eafp x\u1ebfp ch\u1ee9ng minh $\\widehat{O} = \\widehat{I} $ ","temp":"sequence","correct":[[[2],[4],[3],[1],[5]]],"list":[{"point":5,"image":"https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-17.png","left":["n\u00ean $\\widehat{O} = \\widehat{K_{1}} $ (c\u1eb7p g\u00f3c so le trong) ","n\u00ean $\\widehat{I} = \\widehat{K_{1}} $ (c\u1eb7p g\u00f3c so le trong)","M\u1eb7t kh\u00e1c Oy \/\/ In (gi\u1ea3 thi\u1ebft)","Ta c\u00f3 Ox \/\/ Im (gi\u1ea3 thi\u1ebft)","V\u1eady $\\widehat{O} = \\widehat{I} $ "],"top":70,"hint":"","explain":" Ta c\u00f3 Ox \/\/ Im (gi\u1ea3 thi\u1ebft) n\u00ean $\\widehat{O} = \\widehat{K_{1}} $ (c\u1eb7p g\u00f3c so le trong) <br\/> M\u1eb7t kh\u00e1c Oy \/\/ In (gi\u1ea3 thi\u1ebft) n\u00ean $\\widehat{I} = \\widehat{K_{1}} $ (c\u1eb7p g\u00f3c so le trong) <br\/> V\u1eady $\\widehat{O} = \\widehat{I} (= \\widehat{K_{1}}) $ "}]}],"id_ques":1451},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"T\u00ecm c\u00e2u tr\u1ea3 l\u1eddi sai. <br\/> N\u1ebfu a \/\/ b th\u00ec: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C14-10.png' \/><\/center> ","select":["A. $\\widehat{A_{2}} = \\widehat{B_{2}} $","B. $\\widehat{A_{2}} = \\widehat{B_{1}} $","C. $\\widehat{A_{1}} + \\widehat{B_{3}} = 180^{o} $","D. $\\widehat{A_{4}} + \\widehat{B_{4}} = 180^{o} $ "],"hint":"","explain":"H\u01b0\u1edbng d\u1eabn:<\/span><br\/> N\u1ebfu \u0111\u01b0\u1eddng th\u1eb3ng c c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng song song a v\u00e0 b th\u00ec t\u1ea1o th\u00e0nh c\u00e1c c\u1eb7p g\u00f3c so le trong b\u1eb1ng nhau, c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb b\u1eb1ng nhau, c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda, ngo\u00e0i c\u00f9ng ph\u00eda b\u00f9 nhau. <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> C\u00e2u sai l\u00e0 A. V\u00ec <br\/> $\\widehat{A_{2}} $ v\u00e0 $ \\widehat{B_{2}} $ l\u00e0 hai g\u00f3c ngo\u00e0i c\u00f9ng ph\u00eda n\u00ean b\u00f9 nhau. ","column":2}]}],"id_ques":1452},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["115"],["130"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft AB \/\/ CD <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-15.png' \/><\/center> <br\/> T\u00ednh: $\\widehat{A} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} \\\\ \\widehat{B} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":"Ta c\u00f3 AB \/\/ CD n\u00ean $\\widehat{A} + \\widehat{D} = 180^{o} $ (hai g\u00f3c trong c\u00f9ng ph\u00eda) <br\/> $\\Rightarrow \\widehat{A} $$ = 180^{o} - \\widehat{D} \\\\ = 180^{o} - 65^{o} \\\\ = 115^{o} $ <br\/> V\u00ec AB \/\/ CD n\u00ean $\\widehat{B} = \\widehat{BCx} = 130^{o} $ (hai g\u00f3c so le trong)<br\/> <\/br\/>V\u1eady: $ \\widehat{A} = 115^{o} \\\\ \\widehat{B} = 130^{o} $<\/span>"}]}],"id_ques":1453},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["75"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft $\\widehat{BCD} = 115^{o}, \\widehat{BCA} = 40^{o} $ v\u00e0 AB \/\/ CD <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-13.png' \/><\/center> <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{A} $ l\u00e0: $ \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":"Ta c\u00f3: $\\widehat{BCD} = \\widehat{BCA} + \\widehat{ACD} $<br\/> $\\Rightarrow \\widehat{ACD} $$ = \\widehat{BCD} - \\widehat{BCA} \\\\ = 115^{o} - 40^{o} \\\\ = 75^{o} $ <br\/> V\u00ec CD \/\/ AB n\u00ean $\\widehat{A} = \\widehat{ACD} = 75^{o} $ (hai g\u00f3c so le trong)<br\/> <\/br\/>V\u1eady: $ \\widehat{A} = 75^{o} $<\/span>"}]}],"id_ques":1454},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho h\u00ecnh v\u1ebd, bi\u1ebft xy \/\/ mn. Tia BC l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{ABn} $ <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{ACB} $ l\u00e0? <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-12.png' \/> <\/center> ","select":["A. $70^{o} $ ","B. $110^{o}$ ","C. $35^{o} $ ","D. $140^{o} $"],"hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/>N\u1ebfu m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng song song th\u00ec: <br\/> - Hai g\u00f3c so le trong b\u1eb1ng nhau. <br\/> <\/span> B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3 xy \/\/ mn n\u00ean $\\widehat{xAB} = \\widehat{ABn} = 70^{o} $ (hai g\u00f3c so le trong) <br\/> C\u00f3 BC l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{ABn} $ n\u00ean $\\widehat{CBn} = \\dfrac{\\widehat{ABn}}{2} = \\dfrac{70^{o}}{2} = 35^{o}$ <br\/> V\u00ec xy \/\/ mn n\u00ean $\\widehat{ACB} = \\widehat{CBn} = 35^{o} $ (hai g\u00f3c so le trong) <br\/> V\u1eady $\\widehat{ACB} = 35^{o} $ <br\/> <br\/> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 C. <\/span> <\/span> ","column":4}]}],"id_ques":1455},{"time":24,"part":[{"time":3,"title":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","title_trans":"Cho tam gi\u00e1c ABC, k\u1ebb tia ph\u00e2n gi\u00e1c Ax c\u1ee7a $\\widehat{BAC} $. T\u1ea1i C k\u1ebb \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi Ax, n\u00f3 c\u1eaft tia \u0111\u1ed1i c\u1ee7a tia AB t\u1ea1i D. <br\/> H\u00e3y s\u1eafp x\u1ebfp ch\u1ee9ng minh $\\widehat{xAB} = \\widehat{ACD} $ ","temp":"sequence","correct":[[[4],[2],[1],[3],[5]]],"list":[{"point":5,"image":"","left":["n\u00ean $\\widehat{xAC} = \\widehat{ACD} $ (hai g\u00f3c so le trong)","n\u00ean $\\widehat{xAB} = \\widehat{xAC}$","Ta c\u00f3 Ax l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{BAC} $ ","M\u1eb7t kh\u00e1c Ax \/\/ CD ","V\u1eady $\\widehat{xAB} = \\widehat{ACD} $"],"top":70,"hint":"","explain":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-11.png' \/><\/center> <br\/> Ta c\u00f3 Ax l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{BAC} $ n\u00ean $\\widehat{xAB} = \\widehat{xAC}$. <br\/> M\u1eb7t kh\u00e1c Ax \/\/ CD n\u00ean $\\widehat{xAC} = \\widehat{ACD} $ (hai g\u00f3c so le trong). <br\/> V\u1eady $\\widehat{xAB} = \\widehat{ACD} (= \\widehat{xAC})$ "}]}],"id_ques":1456},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["40"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft BC \/\/ AD <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-10.png' \/><\/center> <br\/> T\u00ednh $ y = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":"Ta c\u00f3 BC \/\/ AD n\u00ean: <br\/> $ \\widehat{B} + \\widehat{A} = 180^{o} $ (hai g\u00f3c trong c\u00f9ng ph\u00eda) <br\/> $ \\Rightarrow \\widehat{A} $ $ = 180^{o} - \\widehat{B} \\\\ = 180^{o} - 110^{o} \\\\ = 70^{o} $ <br\/> M\u1eb7t kh\u00e1c $\\widehat{A} = y + 30^{0} $ <br\/> $ \\Rightarrow y $$= \\widehat{A} - 30^{0} \\\\ = 70^{o} - 30^{o} \\\\ = 40^{o} $<br\/> <\/br\/>V\u1eady: $ y = 40^{o} $<\/span>"}]}],"id_ques":1457},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["42"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-09.png' \/><\/center> <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{B_{3}} $ l\u00e0: $ \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":"Ta c\u00f3 a \/\/ b n\u00ean: <br\/> $ \\widehat{A_{1}} = \\widehat{B_{4}} = 138^{o} $ (hai g\u00f3c \u0111\u1ed3ng v\u1ecb) <br\/> M\u00e0 $ \\widehat{B_{3}} + \\widehat{B_{4}} = 180^{o} $ (hai g\u00f3c k\u1ec1 b\u00f9) <br\/> $ \\Rightarrow \\widehat{B_{3}} $ $ = 180^{o} - \\widehat{B_{4}} \\\\ = 180^{o} - 138^{o} \\\\ = 42^{o} $ <br\/> <\/br\/>V\u1eady: $ \\widehat{B_{3}} = 42^{o} $<\/span>"}]}],"id_ques":1458},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" T\u00ecm c\u00e2u tr\u1ea3 l\u1eddi sai. <br\/> Cho h\u00ecnh v\u1ebd, bi\u1ebft AB \/\/ CD. Khi \u0111\u00f3: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-07.png' \/> <\/center> ","select":["A. $\\widehat{AMN} = \\widehat{MND} $ ","B. $\\widehat{AMK} = \\widehat{CNK} $ ","C. $\\widehat{AMK} = \\widehat{DNH} $ ","D. $\\widehat{CNH} = \\widehat{AMK} $"],"hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/>N\u1ebfu m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng song song th\u00ec: <br\/> - Hai g\u00f3c so le trong b\u1eb1ng nhau. <br\/> - Hai g\u00f3c \u0111\u1ed3ng v\u1ecb b\u1eb1ng nhau. <br\/> - Hai g\u00f3c trong c\u00f9ng ph\u00eda b\u00f9 nhau. <br\/> <\/span> B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3 AB \/\/ CD n\u00ean: <br\/> A. $\\widehat{AMN} = \\widehat{MND} $ (hai g\u00f3c so le trong) <br\/> B. $\\widehat{AMK} = \\widehat{CNK} $(hai g\u00f3c \u0111\u1ed3ng v\u1ecb) <br\/> C. $\\widehat{AMK} = \\widehat{DNH} (= \\widehat{CNK}) $ <br\/> D. $\\widehat{CNH} + \\widehat{AMK} = 180^{o} $ (hai g\u00f3c ngo\u00e0i c\u00f9ng ph\u00eda)<br\/> <br\/> V\u1eady c\u00e2u tr\u1ea3 l\u1eddi sai l\u00e0 D. <\/span> <\/span> ","column":2}]}],"id_ques":1459},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["120"],["60"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b v\u00e0 $\\widehat{C_{1}} = 60^{o} $ <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C14-06.png' \/><\/center> <br\/> T\u00ednh: $\\widehat{D_{1}} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o}\\\\ \\widehat{D_{2}} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":"Ta c\u00f3 a \/\/ b n\u00ean: <br\/> $ \\widehat{C_{1}} + \\widehat{D_{1}} = 180^{o} $ (hai g\u00f3c trong c\u00f9ng ph\u00eda) <br\/> $\\Rightarrow \\widehat{D_{1}} $ $ = 180^{o} - \\widehat{C_{1}} \\\\ = 180^{o} - 60^{o} \\\\ = 120^{o} $ <br\/> $\\widehat{C_{1}} = \\widehat{D_{2}} = 60^{o} $ (c\u1eb7p g\u00f3c so le trong) <br\/> <\/br\/>V\u1eady: $ \\widehat{D_{1}} = 120^{o} \\\\ \\widehat{D_{2}} = 60^{o} $<\/span>"}]}],"id_ques":1460},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"V\u1ebd hai \u0111\u01b0\u1eddng th\u1eb3ng a, b sao cho a \/\/ b . <br\/> V\u1ebd \u0111\u01b0\u1eddng th\u1eb3ng c c\u1eaft \u0111\u01b0\u1eddng th\u1eb3ng a t\u1ea1i \u0111i\u1ec3m A. Khi \u0111\u00f3: ","select":["A. $c \\perp b $ t\u1ea1i A","B. c c\u1eaft b ","C. c \/\/ b ","D. $c \\equiv b $ "],"hint":"","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-04.png' \/><\/center> a \/\/ b, \u0111\u01b0\u1eddng th\u1eb3ng c c\u1eaft \u0111\u01b0\u1eddng th\u1eb3ng a t\u1ea1i \u0111i\u1ec3m A khi \u0111\u00f3 \u0111\u01b0\u1eddng th\u1eb3ng c s\u1ebd c\u1eaft \u0111\u01b0\u1eddng th\u1eb3ng b. <br\/> <br\/> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 B. <\/span>","column":4}]}],"id_ques":1461},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["37"]]],"list":[{"point":5,"width":20,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b v\u00e0 $\\widehat{A_{1}} + \\widehat{A_{2}} + \\widehat{A_{3}} = 323^{o} $ <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-03.png' \/><\/center> <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{B_{4}} $ l\u00e0 : $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":" Ta c\u00f3: $\\widehat{A_{1}} + \\widehat{A_{2}} + \\widehat{A_{3}} = 323^{o} $ <br\/> m\u00e0 $\\widehat{A_{2}} + \\widehat{A_{3}} = 180^{o} $ (hai g\u00f3c k\u1ec1 b\u00f9) <br\/> n\u00ean $\\widehat{A_{1}} = 323^{o} - 180^{o} = 143^{o} $ <br\/> Theo \u0111\u1ec1 b\u00e0i c\u00f3 a \/\/ b n\u00ean $\\widehat{B_{3}} = \\widehat{A_{1}} = 143^{o} $ (hai g\u00f3c so le trong) <br\/> C\u00f3 $\\widehat{B_{3}} + \\widehat{B_{4}} = 180^{o} $ (hai g\u00f3c k\u1ec1 b\u00f9) <br\/> $\\Rightarrow \\widehat{B_{4}} $$= 180^{o} - \\widehat{B_{3}} \\\\ = 180^{o} - 143^{o} \\\\= 37^{o} $<br\/> <br\/> V\u1eady $ \\widehat{B_{4}} = 37^{o} $ <\/span> "}]}],"id_ques":1462},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b v\u00e0 c c\u1eaft a t\u1ea1i A, c\u1eaft b t\u1ea1i B. <br\/> Khi \u0111\u00f3 $\\widehat{A_{4}} + \\widehat{B_{1}} = 180^{o}$ <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-02.png' \/><\/center> ","select":["A. V\u00ec l\u00e0 c\u1eb7p g\u00f3c so le trong ","B. V\u00ec l\u00e0 c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda ","C. V\u00ec l\u00e0 c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb ","D. V\u00ec l\u00e0 c\u1eb7p g\u00f3c so le ngo\u00e0i "],"hint":"","explain":"Ta c\u00f3 a \/\/ b v\u00e0 c c\u1eaft a, b l\u1ea7n l\u01b0\u1ee3t t\u1ea1i A, B n\u00ean: <br\/> $\\widehat{A_{4}} + \\widehat{B_{1}} = 180^{o}$ (V\u00ec l\u00e0 c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda ) <br\/> <br\/> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 B. <\/span>","column":2}]}],"id_ques":1463},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b v\u00e0 c c\u1eaft a t\u1ea1i A, c\u1eaft b t\u1ea1i B. <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-02.png' \/><\/center> <br\/> Khi \u0111\u00f3 $\\widehat{A_{4}} = ... $ (v\u00ec l\u00e0 c\u1eb7p g\u00f3c so le trong) ","select":["A. $\\widehat{A_{3}} $ ","B. $\\widehat{B_{2}} $ ","C. $\\widehat{B_{3}} $ ","D. $\\widehat{B_{1}} $"],"hint":"","explain":"Ta c\u00f3 a \/\/ b v\u00e0 c c\u1eaft a, b l\u1ea7n l\u01b0\u1ee3t t\u1ea1i A, B n\u00ean: $\\widehat{A_{4}} = \\widehat{B_{2}}$ (v\u00ec l\u00e0 c\u1eb7p g\u00f3c so le trong) <br\/> <br\/> <br\/> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 B. <\/span>","column":4}]}],"id_ques":1464},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["143"]]],"list":[{"point":5,"width":20,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b v\u00e0 $\\widehat{A_{4}} = 37^{o} $ <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-01.png' \/><\/center> <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{B_{2}} $ l\u00e0 : $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":"Ta c\u00f3 a \/\/ b n\u00ean $\\widehat{A_{4}} + \\widehat{B_{2}} = 180^{o} $ (hai g\u00f3c trong c\u00f9ng ph\u00eda th\u00ec b\u00f9 nhau) <br\/> $\\Rightarrow \\widehat{B_{2}} $ $ = 180^{o} - \\widehat{A_{4}} \\\\ = 180^{o} - 37^{o} \\\\ = 143^{o} $ <br\/> <br\/> V\u1eady $ \\widehat{B_{2}} = 143^{o} $ <\/span> "}]}],"id_ques":1465},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-01.png' \/><\/center> <br\/> So s\u00e1nh $ \\widehat{A_{1}}$ v\u00e0 $\\widehat{B_{4}}$ ","select":["A. $\\widehat{A_{1}} < \\widehat{B_{4}}$ ","B. $\\widehat{A_{1}} = \\widehat{B_{4}}$ ","C. $\\widehat{A_{1}} > \\widehat{B_{4}}$ "],"hint":"","explain":"Ta c\u00f3 a \/\/ b n\u00ean $\\widehat{A_{1}} = \\widehat{B_{4}}$ (hai g\u00f3c \u0111\u1ed3ng v\u1ecb th\u00ec b\u1eb1ng nhau) <br\/> <br\/> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 B. <\/span>","column":3}]}],"id_ques":1466},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["37"]]],"list":[{"point":5,"width":20,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b v\u00e0 $\\widehat{A_{4}} = 37^{o} $ <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv1/img\/H7C15-01.png' \/><\/center> <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{B_{1}} $ l\u00e0 : $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":"Ta c\u00f3 a \/\/ b n\u00ean $\\widehat{B_{1}} = \\widehat{A_{4}} $ (so le trong) <br\/> <br\/> V\u1eady $ \\widehat{B_{1}} = 37^{o} $ <\/span> "}]}],"id_ques":1467},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t \u0111\u1ec3 \u0111i\u1ec1n v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"N\u1ebfu m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng song song th\u00ec t\u1ea1o ra c\u00e1c c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda .................. ","select":["A. b\u00f9 nhau ","B. \u0111\u1ed1i \u0111\u1ec9nh ","C. b\u1eb1ng nhau ","D. k\u1ec1 nhau "],"hint":"","explain":" N\u1ebfu m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng song song th\u00ec t\u1ea1o ra c\u00e1c c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda b\u00f9 nhau. <br\/> <br\/> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 A. <\/span>","column":2}]}],"id_ques":1468},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t \u0111\u1ec3 \u0111i\u1ec1n v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"N\u1ebfu m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng song song th\u00ec t\u1ea1o ra c\u00e1c c\u1eb7p g\u00f3c so le trong ............... ","select":["A. b\u00f9 nhau ","B. \u0111\u1ed1i \u0111\u1ec9nh ","C. b\u1eb1ng nhau ","D. k\u1ec1 nhau "],"hint":"","explain":" N\u1ebfu m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng song song th\u00ec t\u1ea1o ra c\u00e1c c\u1eb7p g\u00f3c so le trong b\u1eb1ng nhau. <br\/> <br\/> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 C. <\/span>","column":2}]}],"id_ques":1469},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["t","t","f","f"]],"list":[{"point":5,"image":"","ques":"Trong c\u00e1c ph\u00e1t bi\u1ec3u sau, ph\u00e1t bi\u1ec3u n\u00e0o di\u1ec5n \u0111\u1ea1t \u0111\u00fang n\u1ed9i dung c\u1ee7a ti\u1ec1n \u0111\u00ea \u01a0-clit. ","col_name":["","\u0110\u00fang","Sai"],"arr_ques":["N\u1ebfu qua \u0111i\u1ec3m M n\u1eb1m ngo\u00e0i \u0111\u01b0\u1eddng th\u1eb3ng a c\u00f3 hai \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi a th\u00ec ch\u00fang tr\u00f9ng nhau. ","Cho \u0111i\u1ec3m M \u1edf ngo\u00e0i \u0111\u01b0\u1eddng th\u1eb3ng a. \u0110\u01b0\u1eddng th\u1eb3ng \u0111i qua M v\u00e0 song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng a l\u00e0 duy nh\u1ea5t.","C\u00f3 duy nh\u1ea5t m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng cho tr\u01b0\u1edbc","Qua \u0111i\u1ec3m M n\u1eb1m ngo\u00e0i \u0111\u01b0\u1eddng th\u1eb3ng a, c\u00f3 \u00edt nh\u1ea5t m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi a. "],"hint":"","explain":["","","",""]}]}],"id_ques":1470}],"lesson":{"save":0,"level":1}}

Em chưa làm xong câu này