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Home Lớp 6 Toán lớp 6 - Sách kết nối tri thứcBài tập cơ bản

{"common":{"save":0,"post_id":"4815","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8328","post_id":"4815","mon_id":"1158113","chapter_id":"1158117","question":"Vi\u1ebft g\u1ecdn tích sau b\u1eb1ng cách dùng l\u0169y th\u1eeba: <\/p>3 . 3 . 3 . 3 . 3<\/p>","options":["3$^4$<\/span>","3$^5$<\/span>","3 . 5"],"correct":"2","level":"1","hint":"L\u0169y th\u1eeba b\u1eadc n c\u1ee7a s\u1ed1 t\u1ef1 nhiên a là tích c\u1ee7a n th\u1eeba s\u1ed1 b\u1eb1ng nhau, m\u1ed7i th\u1eeba s\u1ed1 b\u1eb1ng a:<\/p>a$^n$<\/span> = a . a . ... . a      (có n th\u1eeba s\u1ed1 a, n∈$\\mathbb{N}^*$<\/span>)<\/p>","answer":"Vi\u1ebft g\u1ecdn tích sau b\u1eb1ng cách dùng l\u0169y th\u1eeba: <\/p>3 . 3 . 3 . 3 . 3 = 3$^5$<\/span>  (có 5 th\u1eeba s\u1ed1 3 nhân l\u1ea1i v\u1edbi nhau)<\/p>V\u1eady \u0111áp án \u0111úng là 3$^5$<\/span><\/strong><\/span><\/p>","type":"choose","extra_type":"shape2","time":"0","user_id":"132","test":"1","date":"2021-10-04 14:55:51","option_type":"math","len":0},{"id":"8331","post_id":"4815","mon_id":"1158113","chapter_id":"1158117","question":"Vi\u1ebft g\u1ecdn tích sau b\u1eb1ng cách dùng l\u0169y th\u1eeba: <\/p>2 . 2 . 3 . 3 . 3. 3<\/p>","options":["2$^4$<\/span> . 3$^4$<\/span>","2$^4$<\/span> . 3$^2$<\/span>","2$^2$<\/span> . 3$^4$<\/span>"],"correct":"3","level":"1","hint":"L\u0169y th\u1eeba b\u1eadc n c\u1ee7a s\u1ed1 t\u1ef1 nhiên a là tích c\u1ee7a n th\u1eeba s\u1ed1 b\u1eb1ng nhau, m\u1ed7i th\u1eeba s\u1ed1 b\u1eb1ng a:<\/p>a$^n$<\/span> = a . a . ... . a      (có n th\u1eeba s\u1ed1 a,  n∈$\\mathbb{N}^*$<\/span>)<\/p>","answer":"Vì tích 2 . 2 . 3 . 3 . 3. 3 có 2 th\u1eeba s\u1ed1 b\u1eb1ng 2 và 4 th\u1eeba s\u1ed1 b\u1eb1ng 3 nên<\/p>2 . 2 . 3 . 3 . 3. 3 = 2$^2$<\/span> . 3$^4$<\/span><\/p>V\u1eady \u0111áp án \u0111úng là 2$^2$<\/span> . 3$^4$<\/span><\/strong><\/span><\/p>","type":"choose","extra_type":"shape1","time":"0","user_id":"132","test":"1","date":"2021-10-04 15:00:47","option_type":"math","len":0},{"id":"8332","post_id":"4815","mon_id":"1158113","chapter_id":"1158117","question":"Tính: <\/p>17$^2$<\/span> = ?<\/p>","options":["289","298","17"],"correct":"1","level":"1","hint":"L\u0169y th\u1eeba b\u1eadc n c\u1ee7a s\u1ed1 t\u1ef1 nhiên a là tích c\u1ee7a n th\u1eeba s\u1ed1 b\u1eb1ng nhau, m\u1ed7i th\u1eeba s\u1ed1 b\u1eb1ng a:<\/p>a$^n$<\/span> = a . a . ... . a      (có n th\u1eeba s\u1ed1 a,  n∈$\\mathbb{N}^*$<\/span>)<\/p>","answer":"17$^2$<\/span> = 17 . 17 = 289<\/p>V\u1eady \u0111áp án \u0111úng là 289<\/strong><\/span><\/p>","type":"choose","extra_type":"flower","time":"0","user_id":"132","test":"1","date":"2021-10-04 15:02:54","option_type":"txt","len":0}]}