{"common":{"save":0,"post_id":"9290","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7533","post_id":"9290","mon_id":"1159850","chapter_id":"1160021","question":"<p data-pm-slice=\"0 0 []\">Kho\u1ea3ng nhi\u1ec7t \u0111\u1ed9 nào là t\u1ed1i thi\u1ec3u cây b\u1eaft \u0111\u1ea7u th\u1ef1c hi\u1ec7n hô h\u1ea5p?<\/p>","options":["A. (-5 0C) - (5 0C), tùy theo lo\u1ea1i cây \u1edf các vùng sinh thái khác nhau","B. (0 0C) - (10 0C), tùy theo lo\u1ea1i cây \u1edf các vùng sinh thái khác nhau.","C. (5 0C) - (10 0C), tùy theo lo\u1ea1i cây \u1edf các vùng sinh thái khác nhau","D. (10 0C) - (20 0C), tùy theo lo\u1ea1i cây \u1edf các vùng sinh thái khác nhau."],"correct":"2","level":"2","hint":"<p>Hãy nh\u1edb nhi\u1ec7t \u0111\u1ed9 th\u1ea5p nh\u1ea5t mà t\u1ebf bào v\u1eabn b\u1eaft \u0111\u1ea7u hô h\u1ea5p, th\u01b0\u1eddng vài \u0111\u1ed9 C trên 0.<\/p>","answer":"<p>\u0110áp án \u0111úng:<span style=\"color:#16a085;\"> <strong>B. (0 0C) - (10 0C), tùy theo lo\u1ea1i cây \u1edf các vùng sinh thái khác nhau.<\/strong><\/span><\/p><p>Nhi\u1ec7t \u0111\u1ed9 t\u1ed1i thi\u1ec3u mà cây b\u1eaft \u0111\u1ea7u th\u1ef1c hi\u1ec7n hô h\u1ea5p th\u01b0\u1eddng n\u1eb1m trong kho\u1ea3ng t\u1eeb <strong data-end=\"94\" data-start=\"78\">0°C \u0111\u1ebfn 10°C<\/strong>, tùy vào lo\u1ea1i cây và vùng sinh thái.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-05-21 10:19:03","option_type":"txt","len":3},{"id":"7534","post_id":"9290","mon_id":"1159850","chapter_id":"1160021","question":"<p data-pm-slice=\"0 0 []\">Hô h\u1ea5p \u1edf th\u1ef1c v\u1eadt là gì?<\/p>","options":["A. Quá trình chuy\u1ec3n \u0111\u1ed5i n\u0103ng l\u01b0\u1ee3ng c\u1ee7a t\u1ebf bào s\u1ed1ng. Trong \u0111ó, các phân t\u1eed Amylase b\u1ecb phân gi\u1ea3i \u0111\u1ebfn O2 và H2O, \u0111\u1ed3ng th\u1eddi n\u0103ng l\u01b0\u1ee3ng \u0111\u01b0\u1ee3c gi\u1ea3i phóng và m\u1ed9t ph\u1ea7n n\u0103ng l\u01b0\u1ee3ng \u0111ó \u0111\u01b0\u1ee3c tích l\u0169y trong ATP.","B. Quá trình chuy\u1ec3n \u0111\u1ed5i n\u0103ng l\u01b0\u1ee3ng c\u1ee7a t\u1ebf bào s\u1ed1ng. Trong \u0111ó, các phân t\u1eed cacbohidrat b\u1ecb phân gi\u1ea3i \u0111\u1ebfn CO2 và H2O, \u0111\u1ed3ng th\u1eddi n\u0103ng l\u01b0\u1ee3ng \u0111\u01b0\u1ee3c gi\u1ea3i phóng và m\u1ed9t ph\u1ea7n n\u0103ng l\u01b0\u1ee3ng \u0111ó \u0111\u01b0\u1ee3c tích l\u0169y trong ATP.","C. Quá trình chuy\u1ec3n \u0111\u1ed5i n\u0103ng l\u01b0\u1ee3ng c\u1ee7a t\u1ebf bào s\u1ed1ng. Trong \u0111ó, các phân t\u1eed Glutamine b\u1ecb phân gi\u1ea3i \u0111\u1ebfn CO2 và H2O, \u0111\u1ed3ng th\u1eddi n\u0103ng l\u01b0\u1ee3ng \u0111\u01b0\u1ee3c gi\u1ea3i phóng và m\u1ed9t ph\u1ea7n n\u0103ng l\u01b0\u1ee3ng \u0111ó \u0111\u01b0\u1ee3c tích l\u0169y trong ATP.","D. Quá trình chuy\u1ec3n \u0111\u1ed5i n\u0103ng l\u01b0\u1ee3ng c\u1ee7a t\u1ebf bào s\u1ed1ng. Trong \u0111ó, các phân t\u1eed Lysine b\u1ecb phân gi\u1ea3i \u0111\u1ebfn O2 và H2O, \u0111\u1ed3ng th\u1eddi n\u0103ng l\u01b0\u1ee3ng \u0111\u01b0\u1ee3c gi\u1ea3i phóng và m\u1ed9t ph\u1ea7n n\u0103ng l\u01b0\u1ee3ng \u0111ó \u0111\u01b0\u1ee3c tích l\u0169y trong ATP."],"correct":"2","level":"2","hint":"<p>Hãy \u0111\u1ecbnh ngh\u0129a hô h\u1ea5p: phân gi\u1ea3i ch\u1ea5t h\u1eefu c\u01a1, gi\u1ea3i phóng n\u0103ng l\u01b0\u1ee3ng d\u01b0\u1edbi d\u1ea1ng ATP.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>B. Quá trình chuy\u1ec3n \u0111\u1ed5i n\u0103ng l\u01b0\u1ee3ng c\u1ee7a t\u1ebf bào s\u1ed1ng. Trong \u0111ó, các phân t\u1eed cacbohidrat b\u1ecb phân gi\u1ea3i \u0111\u1ebfn CO2và H2O, \u0111\u1ed3ng th\u1eddi n\u0103ng l\u01b0\u1ee3ng \u0111\u01b0\u1ee3c gi\u1ea3i phóng và m\u1ed9t ph\u1ea7n n\u0103ng l\u01b0\u1ee3ng \u0111ó \u0111\u01b0\u1ee3c tích l\u0169y trong ATP.<\/strong><\/span><\/p><p data-end=\"126\" data-start=\"41\">Hô h\u1ea5p \u1edf th\u1ef1c v\u1eadt là <strong data-end=\"115\" data-start=\"62\">quá trình chuy\u1ec3n \u0111\u1ed5i n\u0103ng l\u01b0\u1ee3ng trong t\u1ebf bào s\u1ed1ng<\/strong>, trong \u0111ó:<\/p><p data-end=\"180\" data-start=\"130\"><strong data-end=\"145\" data-start=\"130\">Cacbohidrat<\/strong> (ch\u1ee7 y\u1ebfu là glucose) b\u1ecb phân gi\u1ea3i,<\/p><p data-end=\"205\" data-start=\"183\">T\u1ea1o ra <strong data-end=\"204\" data-start=\"190\">CO\u2082 và H\u2082O<\/strong>,<\/p><p data-end=\"335\" data-start=\"208\"><strong data-end=\"233\" data-start=\"208\">Gi\u1ea3i phóng n\u0103ng l\u01b0\u1ee3ng<\/strong>, m\u1ed9t ph\u1ea7n n\u0103ng l\u01b0\u1ee3ng \u0111ó \u0111\u01b0\u1ee3c <strong data-end=\"293\" data-start=\"263\">tích l\u0169y trong phân t\u1eed ATP<\/strong> \u0111\u1ec3 t\u1ebf bào s\u1eed d\u1ee5ng cho các ho\u1ea1t \u0111\u1ed9ng s\u1ed1ng.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-05-22 09:55:41","option_type":"txt","len":3},{"id":"7535","post_id":"9290","mon_id":"1159850","chapter_id":"1160021","question":"<p data-pm-slice=\"0 0 []\">Có bao nhiêu phát bi\u1ec3u có n\u1ed9i dung \u0111úng trong s\u1ed1 nh\u1eefng phát bi\u1ec3u sau?<\/p><p>1. Quá trình h\u1ea5p th\u1ee5 O2 và gi\u1ea3i phóng CO2 \u1edf ngoài sáng là quá trình phân gi\u1ea3i k\u1ecb khí.<\/p><p>2. Trong hô h\u1ea5p sáng, enzim cacboxilaza chuy\u1ec3n thành enzim ôxigenaza ôxi hóa RiDP th\u1ea3i CO2 x\u1ea3y ra k\u1ebf ti\u1ebfp l\u1ea7n l\u01b0\u1ee3t \u1edf các bào quan l\u1ee5c l\u1ea1p th\u1ec3 perôxixôm.<\/p><p>3. N\u01a1i di\u1ec5n ra hô h\u1ea5p m\u1ea1nh nh\u1ea5t \u1edf th\u1ef1c v\u1eadt là \u1edf lá.<\/p><p>4. Trong quá trình hô h\u1ea5p, m\u1ed9t l\u01b0\u1ee3ng n\u0103ng l\u01b0\u1ee3ng d\u01b0\u1edbi d\u1ea1ng nhi\u1ec7t \u0111\u01b0\u1ee3c gi\u1ea3i phóng ra nh\u1eb1m m\u1ee5c \u0111ích giúp t\u1ed5ng h\u1ee3p các ch\u1ea5t h\u1eefu c\u01a1.<\/p>","options":["A. 1","B. 0","C. 2","D. 3"],"correct":"2","level":"2","hint":"<p>Hãy ki\u1ec3m tra t\u1eebng phát bi\u1ec3u v\u1ec1 hô h\u1ea5p sáng, hô h\u1ea5p m\u1ea1nh \u1edf \u0111âu và n\u0103ng l\u01b0\u1ee3ng gi\u1ea3i phóng.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>B. 0<\/strong><\/span><\/p><p data-end=\"47\" data-start=\"23\"><strong data-end=\"47\" data-start=\"23\">Gi\u1ea3i thích:<\/strong><\/p><p data-end=\"124\" data-start=\"52\"><strong data-end=\"59\" data-start=\"52\">1. Sai<\/strong> – H\u1ea5p th\u1ee5 O\u2082, th\u1ea3i CO\u2082 là <strong data-end=\"98\" data-start=\"86\">hi\u1ebfu khí<\/strong>, không ph\u1ea3i <strong data-end=\"121\" data-start=\"111\">k\u1ecb khí<\/strong>.<\/p><p data-end=\"264\" data-start=\"128\"><strong data-end=\"135\" data-start=\"128\">2. Sai<\/strong> – Hô h\u1ea5p sáng x\u1ea3y ra \u1edf <strong data-end=\"191\" data-start=\"159\">l\u1ee5c l\u1ea1p → peroxixom → ti th\u1ec3<\/strong>, nh\u01b0ng <strong data-end=\"232\" data-start=\"199\">CO\u2082 không th\u1ea3i ra \u1edf peroxixom<\/strong> → phát bi\u1ec3u <strong data-end=\"261\" data-is-only-node=\"\" data-start=\"245\">sai chi ti\u1ebft<\/strong>.<\/p><p data-end=\"347\" data-start=\"268\"><strong data-end=\"275\" data-start=\"268\">3. Sai<\/strong> – Hô h\u1ea5p m\u1ea1nh nh\u1ea5t \u1edf <strong data-end=\"303\" data-start=\"297\">r\u1ec5<\/strong> và <strong data-end=\"323\" data-start=\"307\">mô phân sinh<\/strong>, <strong data-end=\"344\" data-is-only-node=\"\" data-start=\"325\">không ph\u1ea3i \u1edf lá<\/strong>.<\/p><p data-end=\"440\" data-start=\"351\"><strong data-end=\"358\" data-start=\"351\">4. Sai<\/strong> – <strong data-end=\"370\" data-start=\"361\">Nhi\u1ec7t<\/strong> là n\u0103ng l\u01b0\u1ee3ng <strong data-end=\"399\" data-start=\"385\">th\u1ea5t thoát<\/strong>, <strong data-end=\"439\" data-is-only-node=\"\" data-start=\"401\">không dùng \u0111\u1ec3 t\u1ed5ng h\u1ee3p ch\u1ea5t h\u1eefu c\u01a1<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-05-22 09:56:58","option_type":"txt","len":0}]}