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{"save":1,"level":1,"time":"50","total":40,"point":5,"segment":[{"id":"4642","test_id":"520","question":"<p>Cho \u0111o\u1ea1n dây d\u1eabn MO = 10 cm \u0111\u01b0\u1ee3c g\u1ea5p t\u1ea1i trung \u0111i\u1ec3m N c\u1ee7a dây và \u0111\u1eb7t vào vùng có t\u1eeb tr\u01b0\u1eddng \u0111\u1ec1u, có các véct\u01a1 c\u1ea3m \u1ee9ng t\u1eeb nh\u01b0 hình v\u1ebd. Bi\u1ebft <span class=\"math-tex\">$I=2A$<\/span>, <span class=\"math-tex\">$B=0,01T$<\/span>, <span class=\"math-tex\">$\\alpha=30^0$<\/span>. L\u1ef1c t\u1eeb tác d\u1ee5ng lên \u0111o\u1ea1n MN<\/p><p><span class=\"svgedit\"><svg height=\"164\" width=\"263\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\"> <g>\\n<title><\/title>\\n<rect fill=\"#fff\" height=\"166\" id=\"canvas_background\" width=\"265\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" id=\"canvasGrid\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" id=\"svg_2\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g>\\n<title><\/title>\\n<image height=\"164\" id=\"svg_1\" width=\"263\" x=\"-4.5\" 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\" y=\"-5\"><\/image> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"20\" font-weight=\"bold\" id=\"svg_3\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"231.00001\" xml:space=\"preserve\" y=\"55.70739\">O<\/text> <\/g> <\/svg><\/span><\/p>","options":["<strong>A.<\/strong> có \u0111\u1ed9 l\u1edbn là <span class=\"math-tex\">$5.10^{-4}\\;N$<\/span>.","<strong>B.<\/strong> có ph\u01b0\u01a1ng vuông góc m\u1eb7t ph\u1eb3ng hình v\u1ebd, chi\u1ec1u t\u1eeb ngoài vào trong.","<strong>C.<\/strong> có ph\u01b0\u01a1ng vuông góc v\u1edbi \u0111\u01b0\u1eddng s\u1ee9c t\u1eeb, chi\u1ec1u t\u1eeb d\u01b0\u1edbi lên.","<strong>D.<\/strong> cân b\u1eb1ng v\u1edbi l\u1ef1c t\u1eeb tác d\u1ee5ng lên NO."],"correct":"1","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>A.<\/strong> có \u0111\u1ed9 l\u1edbn là <span class=\"math-tex\">$5.10^{-4}\\;N$<\/span>.<\/span><\/p><p>MO = 10 cm ⇒ MN = 5 cm = 0,05 m (vì N là trung \u0111i\u1ec3m MO).<\/p><p>Ta có <span class=\"math-tex\">$F=IlB\\sin\\alpha=I.MN.\\sin30^0=2.0,05.0,01.\\sin30^0=5.10^{-4}\\;N$<\/span>.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-06 07:50:19"},{"id":"4644","test_id":"520","question":"<p>Khi nói v\u1ec1 mô hình \u0111\u1ed9ng h\u1ecdc phân t\u1eed, phát bi\u1ec3u nào sau \u0111ây \u0111úng?<\/p>","options":["<strong>A.<\/strong> Gi\u1eefa các phân t\u1eed ch\u1ec9 có các l\u1ef1c \u0111\u1ea9y.","<strong>B.<\/strong> Nhi\u1ec7t \u0111\u1ed9 c\u1ee7a v\u1eadt càng cao, chuy\u1ec3n \u0111\u1ed9ng nhi\u1ec7t c\u1ee7a các phân t\u1eed càng nhanh.","<strong>C.<\/strong> Các phân t\u1eed c\u1ea5u t\u1ea1o nên v\u1eadt chuy\u1ec3n \u0111\u1ed9ng không ng\u1eebng theo cùng m\u1ed9t h\u01b0\u1edbng.","<strong>D.<\/strong> Gi\u1eefa các phân t\u1eed không có kho\u1ea3ng cách."],"correct":"2","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B.<\/strong> Nhi\u1ec7t \u0111\u1ed9 c\u1ee7a v\u1eadt càng cao, chuy\u1ec3n \u0111\u1ed9ng nhi\u1ec7t c\u1ee7a các phân t\u1eed càng nhanh.<\/span><\/p><p>- Các ch\u1ea5t \u0111\u01b0\u1ee3c c\u1ea5u t\u1ea1o t\u1eeb các h\u1ea1t riêng bi\u1ec7t là phân t\u1eed, gi\u1eefa các phân t\u1eed luôn có kho\u1ea3ng cách.<\/p><p>- Các phân t\u1eed chuy\u1ec3n \u0111\u1ed9ng h\u1ed7n lo\u1ea1n không ng\u1eebng.<\/p><p>- Nhi\u1ec7t \u0111\u1ed9 c\u1ee7a v\u1eadt càng cao thì các phân t\u1eed c\u1ea5u t\u1ea1o nên v\u1eadt chuy\u1ec3n \u0111\u1ed9ng càng nhanh.<\/p><p>- Gi\u1eefa các phân t\u1eed c\u1ea5u t\u1ea1o nên v\u1eadt có l\u1ef1c hút và l\u1ef1c \u0111\u1ea9y.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-06 07:56:50"}]}