{"save":1,"level":1,"time":"50","total":40,"point":5,"segment":[{"id":"4536","test_id":"518","question":"<p>M\u1ed9t nhi\u1ec7t k\u1ebf b\u1ecb h\u1ecfng c&oacute; hai nhi\u1ec7t \u0111\u1ed9 l&agrave;m m\u1ed1c l&agrave;: \u0111i\u1ec3m \u0111&oacute;ng b\u0103ng c\u1ee7a n\u01b0\u1edbc tinh khi\u1ebft v&agrave; \u0111i\u1ec3m s&ocirc;i c\u1ee7a n\u01b0\u1edbc tinh khi\u1ebft \u1edf &aacute;p su\u1ea5t ti&ecirc;u chu\u1ea9n l\u1ea7n l\u01b0\u1ee3t l&agrave; &ndash;2&deg;C v&agrave; 102&deg;C. N\u1ebfu s\u1ed1 ch\u1ec9 nhi\u1ec7t \u0111\u1ed9 \u0111o b\u1edfi nhi\u1ec7t k\u1ebf n&agrave;y l&agrave; 50&deg;C th&igrave; nhi\u1ec7t \u0111\u1ed9 \u0111&uacute;ng trong thang Celsius l&agrave; bao nhi&ecirc;u?<\/p>","options":["<strong>A.<\/strong>&nbsp;50&deg;C.","<strong>B.<\/strong>&nbsp;48&deg;C.","<strong>C.<\/strong>&nbsp;55&deg;C.","<strong>D.<\/strong>&nbsp;52&deg;C."],"correct":"1","answer":"<p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>A.<\/strong>&nbsp;50&deg;C.<\/span><\/p><p>Ta c&oacute;:&nbsp;<span class=\"math-tex\">$\\dfrac{t-0}{100-0}=\\dfrac{50-(-2)}{102-(-2)}$<\/span>&nbsp;&rArr; t = 50&deg;C.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-05 09:23:00"},{"id":"4537","test_id":"518","question":"<p>Ph\u01b0\u01a1ng tr&igrave;nh tr\u1ea1ng th&aacute;i c\u1ee7a kh&iacute;&nbsp;l&iacute; t\u01b0\u1edfng l&agrave;:<\/p>","options":["<strong>A.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{p_1V_1}{T_1}=\\dfrac{p_2V_2}{T_2}$<\/span>.","<strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{p_1}{T_1}=\\dfrac{p_2}{T_2}$<\/span>.","<strong>C.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{p_1V_1}{T_2}=\\dfrac{p_2V_2}{T_1}$<\/span>.","<strong>D.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{V_1}{T_1}=\\dfrac{V_2}{T_2}$<\/span>."],"correct":"1","answer":"<p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>A.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{p_1V_1}{T_1}=\\dfrac{p_2V_2}{T_2}$<\/span>.<\/span><\/p><p>Ph\u01b0\u01a1ng tr&igrave;nh tr\u1ea1ng th&aacute;i c\u1ee7a kh&iacute;&nbsp;l&iacute; t\u01b0\u1edfng l&agrave;&nbsp;<span class=\"math-tex\">$\\dfrac{p_1V_1}{T_1}=\\dfrac{p_2V_2}{T_2}$<\/span>.<\/p>","type":"choose","user_id":"131","test":"0","date":"2025-06-05 09:25:32"}]}