{"save":1,"level":1,"time":"90","total":34,"point":5,"segment":[{"id":"3943","test_id":"492","question":"<p>T&igrave;m nguy&ecirc;n h&agrave;m c\u1ee7a h&agrave;m s\u1ed1&nbsp;<span class=\"math-tex\">$f(x)=\\dfrac{1}{5x-12}$<\/span><\/p>","options":["A.&nbsp;<span class=\"math-tex\">$\\int\\dfrac{dx}{5x-12}=\\dfrac{1}{5}\\ln|12-5x|+C$<\/span>","B.&nbsp;<span class=\"math-tex\">$\\int\\dfrac{dx}{5x-12}=-\\dfrac{1}{5}\\ln|5x-12|+C$<\/span>","C.&nbsp;<span class=\"math-tex\">$\\int\\dfrac{dx}{5x-12}=5\\ln|5x-12|+C$<\/span>","D.&nbsp;<span class=\"math-tex\">$\\int\\dfrac{dx}{5x-12}=\\ln|5x-12|+C$<\/span>"],"correct":"1","answer":"<p>\u0110&aacute;p &aacute;n \u0111&uacute;ng l&agrave;:&nbsp;<span style=\"color:#16a085;\"><strong>A.&nbsp;<span class=\"math-tex\">$\\displaystyle\\int\\frac{dx}{5x-12}=\\frac{1}{5}\\ln|12-5x|+C$<\/span>.<\/strong><\/span><\/p><p>Ta c&oacute;:&nbsp;<span class=\"math-tex\">$\\displaystyle\\int f(x)dx=\\int\\dfrac{1}{5x-12}dx=\\dfrac{1}{5}\\ln(5x-12)+C$<\/span>.<\/p>","type":"choose","user_id":"126","test":"3","date":"2025-05-16 11:22:53"},{"id":"3944","test_id":"492","question":"<p>Trong kh&ocirc;ng gian Oxyz, ph\u01b0\u01a1ng tr&igrave;nh n&agrave;o d\u01b0\u1edbi \u0111&acirc;y l&agrave; ph\u01b0\u01a1ng tr&igrave;nh ch&iacute;nh t\u1eafc c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng&nbsp;<span class=\"math-tex\">$d: \\begin{cases} x=-1+2t \\\\ y=3t \\\\ z=-3+t \\end{cases}$<\/span>&nbsp;?<\/p>","options":["<strong>A.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y}{3}=\\dfrac{z-3}{-2}$<\/span>","<strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{x-1}{1}=\\dfrac{y}{3}=\\dfrac{z+3}{-2}$<\/span>","<strong>C.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y-3}{3}=\\dfrac{z+3}{1}$<\/span>","<strong>D.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y}{3}=\\dfrac{z+3}{1}$<\/span>"],"correct":"4","answer":"<p>\u0110&aacute;p &aacute;n \u0111&uacute;ng l&agrave;:&nbsp;<span style=\"color:#16a085;\"><strong>D.&nbsp;<span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y}{3}=\\dfrac{z+3}{1}$<\/span>.<\/strong><\/span><\/p><p>\u0110\u01b0\u1eddng th\u1eb3ng d \u0111i qua \u0111i\u1ec3m&nbsp;<span class=\"math-tex\">$(-1;0;-3)$<\/span>&nbsp;v&agrave; c&oacute; m\u1ed9t VTCP l&agrave;&nbsp;<span class=\"math-tex\">$\\overrightarrow{u}=(2;3;1)$<\/span>&nbsp;n&ecirc;n c&oacute; ph\u01b0\u01a1ng tr&igrave;nh ch&igrave;nh t\u1eafc l&agrave;<\/p><p><span class=\"math-tex\">$\\dfrac{x+1}{2}=\\dfrac{y}{3}=\\dfrac{z+3}{1}$<\/span>.<\/p>","type":"choose","user_id":"126","test":"1","date":"2025-05-16 11:54:37"}]}