{"common":{"save":0,"post_id":"7775","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7385","post_id":"7775","mon_id":"1159533","chapter_id":"1159546","question":"<p>Cho h\u1ed7n h\u1ee3p nhôm và s\u1eaft tác d\u1ee5ng v\u1edbi dung d\u1ecbch Cu(NO\u2083)\u2082 thu \u0111\u01b0\u1ee3c dung d\u1ecbch A và ch\u1ea5t r\u1eafn B g\u1ed3m hai kim lo\u1ea1i. Khi cho ch\u1ea5t r\u1eafn B tác d\u1ee5ng v\u1edbi dung d\u1ecbch HCl th\u1ea5y có b\u1ecdt khí thoát ra. Ch\u1ea5t r\u1eafn B không ch\u1ee9a kim lo\u1ea1i nào?<\/p><p> <\/p>","options":["A. Fe và Al ","B. Cu","C. Al","D. Fe"],"correct":"3","level":"3","hint":"<p>- Xác \u0111\u1ecbnh ph\u1ea3n \u1ee9ng gi\u1eefa h\u1ed7n h\u1ee3p nhôm (Al) và s\u1eaft (Fe) v\u1edbi dung d\u1ecbch \u0111\u1ed3ng(II) nitrat (Cu(NO\u2083)\u2082).<br \/>- Xem xét kh\u1ea3 n\u0103ng ph\u1ea3n \u1ee9ng c\u1ee7a Al và Fe v\u1edbi Cu(NO\u2083)\u2082 d\u1ef1a trên dãy ho\u1ea1t \u0111\u1ed9ng hóa h\u1ecdc.<br \/>- Xác \u0111\u1ecbnh thành ph\u1ea7n c\u1ee7a ch\u1ea5t r\u1eafn B và gi\u1ea3i thích t\u1ea1i sao khi cho B tác d\u1ee5ng v\u1edbi HCl l\u1ea1i có khí thoát ra.<br \/>- D\u1ef1a vào các phân tích, xác \u0111\u1ecbnh kim lo\u1ea1i nào không có m\u1eb7t trong ch\u1ea5t r\u1eafn B.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>C. Al<\/strong><\/span><\/p><p>- Nhôm (Al) ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch Cu(NO\u2083)\u2082: Al + Cu(NO\u2083)\u2082 → Al(NO\u2083)\u2083 + Cu<br \/>- S\u1eaft (Fe) c\u0169ng ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch Cu(NO\u2083)\u2082: Fe + Cu(NO\u2083)\u2082 → Fe(NO\u2083)\u2082 + Cu<br \/>- Sau ph\u1ea3n \u1ee9ng: Dung d\u1ecbch A ch\u1ee9a mu\u1ed1i nhôm nitrat và s\u1eaft nitrat. Ch\u1ea5t r\u1eafn B g\u1ed3m hai kim lo\u1ea1i: \u0111\u1ed3ng (Cu) v\u1eeba \u0111\u01b0\u1ee3c t\u1ea1o ra và có th\u1ec3 còn s\u1eaft (Fe) ch\u01b0a ph\u1ea3n \u1ee9ng h\u1ebft.<br \/>- Khi cho ch\u1ea5t r\u1eafn B vào dung d\u1ecbch HCl: \u0110\u1ed3ng (Cu) không ph\u1ea3n \u1ee9ng v\u1edbi HCl, nên không t\u1ea1o khí. S\u1eaft (Fe) ph\u1ea3n \u1ee9ng v\u1edbi HCl, t\u1ea1o ra khí hidro (H\u2082) gây hi\u1ec7n t\u01b0\u1ee3ng s\u1ee7i b\u1ecdt khí: Fe + 2HCl → FeCl\u2082 + H\u2082↑<br \/>- K\u1ebft lu\u1eadn:<\/p><p>+ Ch\u1ea5t r\u1eafn B không có nhôm (Al) vì nhôm \u0111ã ph\u1ea3n \u1ee9ng h\u1ebft v\u1edbi Cu(NO\u2083)\u2082.<br \/>+ Ch\u1ea5t r\u1eafn B ch\u1ee9a \u0111\u1ed3ng (Cu) và s\u1eaft (Fe).<br \/>+ Do \u0111ó, kim lo\u1ea1i không có trong ch\u1ea5t r\u1eafn B là nhôm (Al).<\/p>","type":"choose","extra_type":"cloud","time":"0","user_id":"127","test":"0","date":"2024-10-06 17:05:11","option_type":"txt","len":0},{"id":"7461","post_id":"7775","mon_id":"1159533","chapter_id":"1159546","question":"<p>\u0110\u1ed1t cháy 11,9 gam h\u1ed7n h\u1ee3p g\u1ed3m Zn, Al trong khí Cl2 d\u01b0. Sau khi các ph\u1ea3n \u1ee9ng x\u1ea3y ra hoàn toàn, thu \u0111\u01b0\u1ee3c 40,3 gam h\u1ed7n h\u1ee3p mu\u1ed1i. Th\u1ec3 tích khí Cl2 (\u0111kc) \u0111ã ph\u1ea3n \u1ee9ng là<br \/> <\/p>","options":["<strong>A.<\/strong> 9,916 lít","<strong>B.<\/strong> 7,437 lít","<strong>C.<\/strong> 17,92 lít","<strong>D.<\/strong> 11,2 lít"],"correct":"1","level":"3","hint":"<p>- D\u1ef1a vào ph\u1ea3n \u1ee9ng c\u1ee7a Zn và Al v\u1edbi khí Cl\u2082 \u0111\u1ec3 t\u1ea1o ra các mu\u1ed1i t\u01b0\u01a1ng \u1ee9ng.<\/p><p>- S\u1eed d\u1ee5ng \u0111\u1ecbnh lu\u1eadt b\u1ea3o toàn kh\u1ed1i l\u01b0\u1ee3ng \u0111\u1ec3 tính th\u1ec3 tích khí Cl\u2082 \u0111ã tham gia ph\u1ea3n \u1ee9ng.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>A. 9,916 lít<\/strong><\/span><\/p><p>- Ph\u1ea3n \u1ee9ng c\u1ee7a Zn và Al v\u1edbi Cl\u2082:<br \/>Zn + Cl\u2082 → ZnCl\u2082<br \/>2Al + 3Cl\u2082 → 2AlCl\u2083<\/p><p>- Áp d\u1ee5ng \u0110L BTKL: m<span class=\"math-tex\">$_{Zn, Al}$<\/span> + m<span class=\"math-tex\">$_{Cl_{2}}$<\/span> = m<span class=\"math-tex\">$_{ mu\u1ed1i}$<\/span><\/p><p>=> m<span class=\"math-tex\">$_{Cl_{2}}$<\/span> = 40,3 - 11,9 = 28,4 (gam)<\/p><p>=> n<span class=\"math-tex\">$_{Cl_{2}}$<\/span> = 28,4 \/ 71 = 0,4 (mol)<\/p><p>V\u1eady V<span class=\"math-tex\">$_{Cl_{2}}$<\/span> = n<span class=\"math-tex\">$_{Cl_{2}}$<\/span> . 24,79 = 9,916 (lít)<\/p>","type":"choose","extra_type":"shape2","time":"0","user_id":"127","test":"0","date":"2024-10-08 15:51:08","option_type":"txt","len":0},{"id":"7462","post_id":"7775","mon_id":"1159533","chapter_id":"1159546","question":"<p>Cho dãy các kim lo\u1ea1i: Fe, Cu, Mg, Ag, Al, Na, Ba. S\u1ed1 kim lo\u1ea1i trong dãy ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi dung d\u1ecbch HCl là<\/p>","options":["<strong>A.<\/strong> 4<br \/>\n ","<strong>B.<\/strong> 3 ","<strong>C.<\/strong> 6","<strong>D.<\/strong> 5"],"correct":"4","level":"3","hint":"<p>- Xét v\u1ecb trí c\u1ee7a các kim lo\u1ea1i trong dãy ho\u1ea1t \u0111\u1ed9ng hóa h\u1ecdc.<\/p><p>- Các kim lo\u1ea1i \u0111\u1ee9ng tr\u01b0\u1edbc hydrogen (H) s\u1ebd ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch HCl, gi\u1ea3i phóng khí H\u2082.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>D. 5<\/strong><\/span><\/p><p>- Có 5 kim lo\u1ea1i \u0111\u1ee9ng tr\u01b0\u1edbc H s\u1ebd ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi dung d\u1ecbch HCl là: Fe, Mg, Al, Na, Ba.<\/p><p>- Các kim lo\u1ea1i còn l\u1ea1i không ph\u1ea3n \u1ee9ng v\u1edbi HCl vì \u0111\u1ee9ng sau H trong dãy ho\u1ea1t \u0111\u1ed9ng hóa h\u1ecdc c\u1ee7a kim lo\u1ea1i.<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-10-08 16:15:34","option_type":"txt","len":0}]}