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Home Lớp 9 Khoa học tự nhiên 9 - sách kết nối tri thứcBài tập nâng cao

{"common":{"save":0,"post_id":"7863","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8114","post_id":"7863","mon_id":"1159533","chapter_id":"1159554","question":"S\u1ed1 liên k\u1ebft \u0111\u01a1n trong phân t\u1eed C$_{4}$<\/span>H$_{10}$<\/span> là:<\/p>","options":[" A. <\/strong>10","B. <\/strong>13","C.<\/strong> 14","D. <\/strong>12"],"correct":"2","level":"3","hint":"D\u1ef1a vào \u0111\u1ecbnh ngh\u0129a công th\u1ee9c c\u1ea5u t\u1ea1o c\u1ee7a m\u1ed9t h\u1ee3p ch\u1ea5t h\u1eefu c\u01a1<\/p>C\u2084H\u2081\u2080<\/strong> là alkane, ch\u1ec9 có liên k\u1ebft \u0111\u01a1n<\/strong> gi\u1eefa các nguyên t\u1eed<\/p>","answer":"\u0110áp án \u0111úng: B. 13<\/strong><\/span><\/p>- Liên k\u1ebft C-C<\/strong>: 3 liên k\u1ebft \u0111\u01a1n.<\/p>- Liên k\u1ebft C-H<\/strong>: 10 liên k\u1ebft \u0111\u01a1n.<\/p>","type":"choose","extra_type":"star","time":"0","user_id":"127","test":"0","date":"2024-10-24 13:04:50","option_type":"txt","len":0},{"id":"8115","post_id":"7863","mon_id":"1159533","chapter_id":"1159554","question":"S\u1ed1 công th\u1ee9c c\u1ea5u t\u1ea1o \u1ee9ng v\u1edbi công th\u1ee9c C$_{3}$<\/span>H$_{7}$<\/span>Cl là:<\/p>","options":["A.<\/strong> 4","B. <\/strong>3","C.<\/strong> 1","D.<\/strong> 2"],"correct":"4","level":"3","hint":"\u0110\u1ec3 xác \u0111\u1ecbnh s\u1ed1 công th\u1ee9c c\u1ea5u t\u1ea1o \u1ee9ng v\u1edbi C\u2083H\u2087Cl<\/strong>, hãy xem xét kh\u1ea3 n\u0103ng phân nhánh<\/strong> c\u1ee7a phân t\u1eed:<\/p>- 1-Chloropropane<\/strong>: Nhóm Cl g\u1eafn vào nguyên t\u1eed carbon s\u1ed1 1 trong chu\u1ed7i propan.<\/p>- 2-Chloropropane<\/strong>: Nhóm Cl g\u1eafn vào nguyên t\u1eed carbon s\u1ed1 2 trong chu\u1ed7i propan.<\/p>","answer":"\u0110áp án \u0111úng: D. 2<\/strong><\/span><\/p>Công th\u1ee9c C\u2083H\u2087Cl có 2 công th\u1ee9c c\u1ea5u t\u1ea1o<\/strong>: 1-chloropropane và 2-chloropropane:<\/p>G\u1ed3m: CH$_{3}$<\/span>CH$_{2}$<\/span>CH$_{2}$<\/span>Cl và CH$_{3}$<\/span>CH(Cl)CH$_{3}$<\/span><\/p>","type":"choose","extra_type":"shape1","time":"0","user_id":"127","test":"0","date":"2024-10-24 13:29:27","option_type":"txt","len":0},{"id":"8116","post_id":"7863","mon_id":"1159533","chapter_id":"1159554","question":"Phân t\u1eed ch\u1ea5t h\u1eefu c\u01a1 X có 2 nguyên t\u1ed1 C, H. T\u1ec9 kh\u1ed1i h\u01a1i c\u1ee7a X so v\u1edbi hydrogen là 21. Công th\u1ee9c phân t\u1eed c\u1ee7a X là:<\/p>","options":["A. <\/strong>C$_{4}$<\/span>H$_{8}$<\/span>","B. <\/strong>C$_{3}$<\/span>H$_{8}$<\/span>","C. <\/strong>C$_{3}$<\/span>H$_{6}$<\/span>","D. <\/strong>C$_{6}$<\/span>H$_{6}$<\/span>"],"correct":"3","level":"3","hint":"- Tìm công th\u1ee9c phân t\u1eed c\u1ee7a X d\u1ef1a trên t\u1ec9 kh\u1ed1i h\u01a1i.<\/p>- S\u1eed d\u1ee5ng t\u1ec9 l\u1ec7 \u0111ã cho \u0111\u1ec3 tính kh\u1ed1i l\u01b0\u1ee3ng mol<\/strong> và \u0111\u1ed1i chi\u1ebfu v\u1edbi các công th\u1ee9c phân t\u1eed trong \u0111áp án \u0111\u1ec3 tìm ch\u1ea5t.<\/p>","answer":"\u0110áp án \u0111úng: C. C$_{3}$<\/span>H$_{6}$<\/span><\/strong><\/span><\/p>- T\u1ec9 kh\u1ed1i h\u01a1i c\u1ee7a X so v\u1edbi hydrogen là 21<\/strong>.<\/p>- Kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a H\u2082<\/strong> là 2 g\/mol, nên kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a X là 42 g\/mol.<\/p>C$_{3}$<\/span>H$_{6}$<\/span> có kh\u1ed1i l\u01b0\u1ee3ng mol = 3×12+6×1 = 42 g\/mol.<\/p>","type":"choose","extra_type":"shape2","time":"0","user_id":"127","test":"0","date":"2024-10-24 13:53:27","option_type":"math","len":0}]}