{"common":{"save":0,"post_id":"8999","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6795","post_id":"8999","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">Mu\u1ed1i \u0111\u01b0\u1ee3c làm b\u1ed9t n\u1edf trong th\u1ef1c ph\u1ea9m là<\/p>","options":["A. (NH4)2CO3.","B. Na2CO3.","C. NH4HCO3.","D. NH4Cl."],"correct":"3","level":"3","hint":"<p>Mu\u1ed1i làm b\u1ed9t n\u1edf trong th\u1ef1c ph\u1ea9m: tìm mu\u1ed1i <strong data-end=\"172\" data-start=\"154\">gi\u1ea3i phóng CO\u2082<\/strong> khi nung ho\u1eb7c khi g\u1eb7p axit\/\u0111\u1ed9 \u1ea9m (t\u1ea1o b\u1ecdt khí).<\/p>","answer":"<p>\u0110áp án \u0111úng:<span style=\"color:#16a085;\"><strong> C. NH4HCO3.<\/strong><\/span><\/p><p>Mu\u1ed1i <strong data-end=\"102\" data-start=\"69\">NH\u2084HCO\u2083 (amoni hi\u0111rocacbonat)<\/strong> \u0111\u01b0\u1ee3c dùng làm <strong data-end=\"143\" data-start=\"117\">b\u1ed9t n\u1edf trong th\u1ef1c ph\u1ea9m<\/strong> vì khi <strong data-end=\"164\" data-start=\"151\">gia nhi\u1ec7t<\/strong>, nó phân h\u1ee7y t\u1ea1o ra CO2 và NH3 làm n\u1edf bánh.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-22 08:37:50","option_type":"txt","len":1},{"id":"6796","post_id":"8999","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">H\u1ed7n h\u1ee3p X ch\u1ee9a 2 mol NH3 và 5 mol O2. Cho X qua Pt (xt) và \u0111un \u1edf 900oC, th\u1ea5y có 90% NH3 b\u1ecb oxi hóa. L\u01b0\u1ee3ng O2 còn d\u01b0 là:<\/p>","options":["A. 2,50 mol.","B. 3,50 mol.","C. 1,00 mol.","D. 2,75 mol."],"correct":"4","level":"3","hint":"<p>Vi\u1ebft các P\u01af oxi hóa NH\u2083 (ph\u1ea3i ghi t\u1ec9 l\u1ec7 mol O\u2082 tiêu hao cho m\u1ed7i mol NH\u2083), dùng 90% NH\u2083 b\u1ecb oxi hóa \u0111\u1ec3 tìm mol O\u2082 tiêu th\u1ee5 — ph\u1ea7n còn d\u01b0 = ban \u0111\u1ea7u − tiêu th\u1ee5.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>D. 2,75 mol.<\/strong><\/span><\/p><p>PTHH: 4NH3 + 5O2 -> 4NO + 6H2O<\/p><p data-pm-slice=\"0 0 []\">nNH3 ph\u1ea3n \u1ee9ng = 2 × 0,9 = 1,8 mol.<\/p><p>⇒ nO2 ph\u1ea3n \u1ee9ng = 1,8 × 5 ÷ 4 = 2,25 mol<\/p><p>⇒ nO2 d\u01b0 = 2,75 mol<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-22 08:39:16","option_type":"txt","len":1},{"id":"6797","post_id":"8999","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">\u0110\u1ec3 tách riêng NH3 ra kh\u1ecfi h\u1ed7n h\u1ee3p g\u1ed3m N2, H2, NH3 trong công nghi\u1ec7p ng\u01b0\u1eddi ta \u0111ã<\/p>","options":["A. cho h\u1ed7n h\u1ee3p qua n\u01b0\u1edbc vôi trong d\u01b0.","B. cho h\u1ed7n h\u1ee3p qua b\u1ed9t CuO nung nóng.","C. nén và làm l\u1ea1nh h\u1ed7n h\u1ee3p \u0111\u1ec3 hóa l\u1ecfng NH3.","D. cho h\u1ed7n h\u1ee3p qua dung d\u1ecbch H2SO4 \u0111\u1eb7c."],"correct":"3","level":"3","hint":"<p>Trong công nghi\u1ec7p tách NH\u2083 kh\u1ecfi N\u2082 và H\u2082: ngh\u0129 ph\u01b0\u01a1ng pháp d\u1ef1a trên <strong data-end=\"502\" data-start=\"466\">\u0111i\u1ec3m sôi\/\u0111i\u1ec3m ng\u01b0ng t\u1ee5 khác nhau<\/strong> ho\u1eb7c h\u1ea5p ph\u1ee5\/khuy\u1ebfch tán; ch\u1ecdn ph\u01b0\u01a1ng th\u1ee9c th\u1ef1c t\u1ebf nh\u1ea5t.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>C. nén và làm l\u1ea1nh h\u1ed7n h\u1ee3p \u0111\u1ec3 hóa l\u1ecfng NH3.<\/strong><\/span><\/p><p data-end=\"188\" data-start=\"96\">Trong công nghi\u1ec7p, \u0111\u1ec3 <strong data-end=\"158\" data-start=\"118\">tách NH\u2083 ra kh\u1ecfi h\u1ed7n h\u1ee3p N\u2082, H\u2082, NH\u2083<\/strong>, ng\u01b0\u1eddi ta t\u1eadn d\u1ee5ng tính ch\u1ea5t:<\/p><p data-end=\"282\" data-start=\"192\"><strong data-end=\"211\" data-start=\"192\">NH\u2083 d\u1ec5 hóa l\u1ecfng<\/strong> \u1edf áp su\u1ea5t cao và nhi\u1ec7t \u0111\u1ed9 th\u1ea5p (NH\u2083 có nhi\u1ec7t \u0111\u1ed9 sôi kho\u1ea3ng <strong data-end=\"280\" data-start=\"271\">-33°C<\/strong>),<\/p><p data-end=\"335\" data-start=\"285\">Còn <strong data-end=\"301\" data-start=\"289\">N\u2082 và H\u2082<\/strong> r\u1ea5t khó hóa l\u1ecfng \u1edf \u0111i\u1ec1u ki\u1ec7n này.<\/p><p data-end=\"433\" data-start=\"337\"> <strong data-end=\"368\" data-start=\"340\">Vì v\u1eady, ch\u1ec9 NH\u2083 hóa l\u1ecfng<\/strong>, còn N\u2082 và H\u2082 v\u1eabn \u1edf th\u1ec3 khí → <strong data-end=\"432\" data-start=\"399\">tách \u0111\u01b0\u1ee3c NH\u2083 ra kh\u1ecfi h\u1ed7n h\u1ee3p<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-22 08:40:39","option_type":"txt","len":3}]}