Đề kiểm tra 45 phút - Toán lớp 11 - Tháng 1

Đề kiểm tra 45 phút - Toán lớp 11 - Tháng 1 - Số 1

45:00

{"save":1,"level":1,"time":"45","total":20,"point":5,"segment":[{"id":"423","test_id":"214","question":"Xét các m\u1ec7nh \u0111\u1ec1 sau:<\/p>$(I)$<\/span>. $\\mathop {\\lim }\\limits_{x \\to - \\infty } {x^k} = + \\infty $<\/span> n\u1ebfu k là s\u1ed1 nguyên d\u01b0\u01a1ng ch\u1eb5n<\/p>$(II)$<\/span>. $\\mathop {\\lim }\\limits_{x \\to -+ \\infty } {x^k} = + \\infty $<\/span> n\u1ebfu k là s\u1ed1 nguyên tùy ý<\/p>Trong 2 m\u1ec7nh \u0111\u1ec1 trên thì<\/p>","options":["A. Ch\u1ec9 $(II)$<\/span> \u0111úng","B. Ch\u1ec9 $(I)$<\/span> \u0111úng","C. C\u1ea3 hai \u0111\u1ec1u sai ","D. C\u1ea3 hai \u0111\u1ec1u sai"],"correct":"2","answer":"Ta có $\\mathop {\\lim }\\limits_{x \\to - \\infty } {x^k} = + \\infty $<\/span> v\u1edbi k là s\u1ed1 nguyên d\u01b0\u01a1ng ch\u1eb5n nên $(I)$<\/span> \u0111úng<\/p>$\\mathop {\\lim }\\limits_{x \\to -+ \\infty } {x^k} = + \\infty $<\/span> v\u1edbi $k \\ge 1$<\/span> nên $(II)$<\/span> sai<\/p>\u0110áp án B<\/p>","type":"choose","user_id":"88","test":"2","date":"2020-03-17 21:54:43"},{"id":"424","test_id":"214","question":"Giá tr\u1ecb c\u1ee7a$\\mathop {\\lim }\\limits_{x \\to - 1} \\dfrac{{{x^2} - 3}}{{{x^3} + 2}}$<\/span> b\u1eb1ng<\/p>","options":["A. 1","B. -2","C. $-\\dfrac32$<\/span>","D. 2"],"correct":"2","answer":"Ta có $\\mathop {\\lim }\\limits_{x \\to - 1} \\dfrac{{{x^2} - 3}}{{{x^3} + 2}} = \\dfrac{{{{\\left( { - 1} \\right)}^2} - 3}}{{{{\\left( { - 1} \\right)}^3} + 2}} = - 2$<\/span><\/p>\u0110áp án B<\/p>","type":"choose","user_id":"88","test":"0","date":"2020-03-17 21:57:58"}]}